---
title: "How to simplify and organize imports in Typescript"
date: "2021-10-16"
slug: "how-to-simplify-and-organize-imports-in-typescript"
author: "Dany Paredes"
canonical: "https://danywalls.com/how-to-simplify-and-organize-imports-in-typescript"
description: "Sometimes we have a long list of imports, with files that come from the same place, it makes our code noisy and a bit longer, something like: import { BeersService } from './services/beers.service'; import { WhiskyService } from './services/whiski...."
---
Sometimes we have a long list of imports, with files that come from the same place, it makes our code noisy and a bit longer, something like:
```
import { BeersService } from './services/beers.service';
import { WhiskyService } from './services/whiski.service';
import { WineService } from './services/wine.service';
```
We can simplify it by exposing all files, from a single file, to point to all of them.
Create drinks.ts into the service directory and export all services.
```typescript
export * from './beers.service';
export * from './whiski.service';
export * from './wine.service';
```
Now we can update our files, to the new path.
```typescript
import { BeersService, WhiskyService, WineService } from './services/drinks';
```
> Thanks @lissetteibnz , If rename the filename from drinks.ts to index.ts, Javascript understand the file index like the entrypoint for the directory, so it works only using the directory name.
```typescript
import { BeersService, WhiskyService, WineService } from './services';
```
The code looks clean and easy to ready because all of them comes from the same place.
Photo by Marcin Jozwiak on Unsplash